JEE Main 2007Annual, Paper 1MathematicsMediumCoordinate Geometry478× since 2002If one of the lines of my2+(1−m2)xy−mx2=0m{y^2} + \left( {1 - {m^2}} \right)xy - m{x^2} = 0my2+(1−m2)xy−mx2=0 is a bisector of angle between the lines xy=0,xy = 0,xy=0, then mmm is :AOption A. 111BOption B. 222COption C. −1/2-1/2−1/2DOption D. −2-2−2CheckSkip · show solution
