JEE Main 20241 Feb, Morning shiftMathematicsHardMatrices and Determinants245× since 2002If A=[21−12],B=[1011],C=ABAT\mathrm{A}=\left[\begin{array}{cc}\sqrt{2} & 1 \\ -1 & \sqrt{2}\end{array}\right], \mathrm{B}=\left[\begin{array}{ll}1 & 0 \\ 1 & 1\end{array}\right], \mathrm{C}=\mathrm{ABA}^{\mathrm{T}}A=[2−112],B=[1101],C=ABAT and X=ATC2 A\mathrm{X}=\mathrm{A}^{\mathrm{T}} \mathrm{C}^2 \mathrm{~A}X=ATC2 A, then detX\operatorname{det} \mathrm{X}detX is equal to :AOption A. 243BOption B. 729COption C. 27DOption D. 891CheckSkip · show solution
