JEE Main 202310 Apr, Evening shiftMathematicsMediumMatrices and Determinants245× since 2002If A=15!6!7![5!6!7!6!7!8!7!8!9!]\mathrm{A}=\frac{1}{5 ! 6 ! 7 !}\left[\begin{array}{ccc}5 ! & 6 ! & 7 ! \\ 6 ! & 7 ! & 8 ! \\ 7 ! & 8 ! & 9 !\end{array}\right]A=5!6!7!15!6!7!6!7!8!7!8!9!, then ∣adj(adj(2 A))∣|\operatorname{adj}(\operatorname{adj}(2 \mathrm{~A}))|∣adj(adj(2 A))∣ is equal to :AOption A. 2122^{12}212BOption B. 2202^{20}220COption C. 282^{8}28DOption D. 2162^{16}216CheckSkip · show solution
