JEE Main 20207 Jan, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If Re(z−12z+i)=1{\mathop{\rm Re}\nolimits} \left( {{{z - 1} \over {2z + i}}} \right) = 1Re(2z+iz−1)=1, where z = x + iy, then the point (x, y) lies on a :AOption A. straight line whose slope is 32{3 \over 2}23BOption B. straight line whose slope is −23-{2 \over 3}−32COption C. circle whose diameter is 52{{\sqrt 5 } \over 2}25DOption D. circle whose centre is at (−12,−32)\left( { - {1 \over 2}, - {3 \over 2}} \right)(−21,−23)CheckSkip · show solution