JEE Main 201910 Apr, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002If limx→1x2−ax+bx−1=5\mathop {\lim }\limits_{x \to 1} {{{x^2} - ax + b} \over {x - 1}} = 5x→1limx−1x2−ax+b=5, then a + b is equal to :AOption A. 1BOption B. - 4COption C. - 7DOption D. 5CheckSkip · show solution
