JEE Main 202118 Mar, Morning shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002If limx→0sin−1x−tan−1x3x3\mathop {\lim }\limits_{x \to 0} {{{{\sin }^{ - 1}}x - {{\tan }^{ - 1}}x} \over {3{x^3}}}x→0lim3x3sin−1x−tan−1x is equal to L, then the value of (6L + 1) isAOption A. 16{1 \over 6}61BOption B. 12{1 \over 2}21COption C. 6DOption D. 2CheckSkip · show solution
