JEE Main 202225 Jul, Morning shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002If limn→∞(n2−n−1+nα+β)=0\mathop {\lim }\limits_{n \to \infty } \left( {\sqrt {{n^2} - n - 1} + n\alpha + \beta } \right) = 0n→∞lim(n2−n−1+nα+β)=0, then 8(α+β)8(\alpha+\beta)8(α+β) is equal to :AOption A. 4BOption B. −-−8COption C. −-−4DOption D. 8CheckSkip · show solution
