If m is the slope of a common tangent to the curves (x²)/16 + (y²)/9 = 1 and x² + y² = 12, then 12m² is equal to:

Coordinate Geometry: JEE Main 2022 Mathematics question

JEE Main 2022 · 26 Jun, Evening shift · Q3721

JEE Main 202226 Jun, Evening shiftMathematicsEasyCoordinate Geometry478× since 2002

If m is the slope of a common tangent to the curves

{{{x^2}} \over {16}} + {{{y^2}} \over 9} = 1

and

{x^2} + {y^2} = 12

, then

12{m^2}

is equal to :

JEE Main 2022 · 26 Jun, Evening shift · Q3721

JEE Main 202226 Jun, Evening shiftMathematicsEasyCoordinate Geometry478× since 2002

If m is the slope of a common tangent to the curves

{{{x^2}} \over {16}} + {{{y^2}} \over 9} = 1

and

{x^2} + {y^2} = 12

, then

12{m^2}

is equal to :