Limit, Continuity and Differentiability: JEE Main 2019 Mathematics question

JEE Main 2019 · 12 Apr, Morning shift · Q2711

JEE Main 201912 Apr, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

If m is the minimum value of k for which the function f(x) = x

\sqrt {kx - {x^2}}

is increasing in the interval [0,3] and M is the maximum value of f in [0, 3] when k = m, then the ordered pair (m, M) is equal to :

JEE Main 2019 · 12 Apr, Morning shift · Q2711

JEE Main 201912 Apr, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

If m is the minimum value of k for which the function f(x) = x

\sqrt {kx - {x^2}}

is increasing in the interval [0,3] and M is the maximum value of f in [0, 3] when k = m, then the ordered pair (m, M) is equal to :

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