JEE Main 202622 Jan, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002If limx→0e(a−1)x+2cosbx+(c−2)e−xxcosx−loge(1+x)=2\lim_{x\to0}\frac{e^{(a-1)x}+2\cos bx+(c-2)e^{-x}}{x\cos x-\log_e(1+x)}=2limx→0xcosx−loge(1+x)e(a−1)x+2cosbx+(c−2)e−x=2, then a2+b2+c2a^2+b^2+c^2a2+b2+c2 is equal to :AOption A. 9BOption B. 3COption C. 7DOption D. 5CheckSkip · show solution
