JEE Main 202126 Aug, Evening shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002If (3+i)100=299(p+iq){\left( {\sqrt 3 + i} \right)^{100}} = {2^{99}}(p + iq)(3+i)100=299(p+iq), then p and q are roots of the equation :AOption A. x2−(3−1)x−3=0{x^2} - \left( {\sqrt 3 - 1} \right)x - \sqrt 3 = 0x2−(3−1)x−3=0BOption B. x2+(3+1)x+3=0{x^2} + \left( {\sqrt 3 + 1} \right)x + \sqrt 3 = 0x2+(3+1)x+3=0COption C. x2+(3−1)x−3=0{x^2} + \left( {\sqrt 3 - 1} \right)x - \sqrt 3 = 0x2+(3−1)x−3=0DOption D. x2−(3+1)x+3=0{x^2} - \left( {\sqrt 3 + 1} \right)x + \sqrt 3 = 0x2−(3+1)x+3=0CheckSkip · show solution
