JEE Main 2018Session, Shift 1MathematicsMediumMatrices and Determinants245× since 2002If ∣x−42x2x2xx−42x2x2xx−4∣=(A+Bx)(x−A)2\left| {\matrix{ {x - 4} & {2x} & {2x} \cr {2x} & {x - 4} & {2x} \cr {2x} & {2x} & {x - 4} \cr } } \right| = \left( {A + Bx} \right){\left( {x - A} \right)^2}x−42x2x2xx−42x2x2xx−4=(A+Bx)(x−A)2 then the ordered pair (A, B) is equal to :AOption A. (4, 5)BOption B. (-4, -5)COption C. (-4, 3)DOption D. (-4, 5)CheckSkip · show solution
