JEE Main 20203 Sep, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002If Δ\DeltaΔ = ∣x−22x−33x−42x−33x−44x−53x−55x−810x−17∣\left| {\matrix{ {x - 2} & {2x - 3} & {3x - 4} \cr {2x - 3} & {3x - 4} & {4x - 5} \cr {3x - 5} & {5x - 8} & {10x - 17} \cr } } \right|x−22x−33x−52x−33x−45x−83x−44x−510x−17 = Ax³ + Bx² + Cx + D, then B + C is equal to :AOption A. -1BOption B. -3COption C. 9DOption D. 1CheckSkip · show solution
