JEE Main 201910 Jan, Evening shiftMathematicsMediumVector Algebra184× since 2002If α→\overrightarrow \alphaα = (λ−2)a→+b→\left( {\lambda - 2} \right)\overrightarrow a + \overrightarrow b(λ−2)a+b and β→=(4λ−2)a→+3b→\overrightarrow \beta = \left( {4\lambda - 2} \right)\overrightarrow a + 3\overrightarrow bβ=(4λ−2)a+3b be two given vectors a→\overrightarrow aa and b→\overrightarrow bb are non-collinear. The value of λ\lambdaλ for which vectors α→\overrightarrow \alphaα and β→\overrightarrow \betaβ are collinear, is -AOption A. 4BOption B. 3COption C. −-−3DOption D. −-−4CheckSkip · show solution