JEE Main 2017Session, Shift 1MathematicsMediumDifferential Equations163× since 2002If (2+sinx)dydx+(y+1)cosx=0\left( {2 + \sin x} \right){{dy} \over {dx}} + \left( {y + 1} \right)\cos x = 0(2+sinx)dxdy+(y+1)cosx=0 and y(0) = 1, then y(π2)y\left( {{\pi \over 2}} \right)y(2π) is equal to :AOption A. −23- {2 \over 3}−32BOption B. −13- {1 \over 3}−31COption C. 43{4 \over 3}34DOption D. 13{1 \over 3}31CheckSkip · show solution
