JEE Main 20203 Sep, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If (1+i1−i)m2=(1+i1−i)n3=1{\left( {{{1 + i} \over {1 - i}}} \right)^{{m \over 2}}} = {\left( {{{1 + i} \over {1 - i}}} \right)^{{n \over 3}}} = 1(1−i1+i)2m=(1−i1+i)3n=1, (m, n ∈\in∈ N) then the greatest common divisor of the least values of m and n is _______ .Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution