JEE Main 202227 Jun, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002If y(x)=(xx)x, x>0y(x) = {\left( {{x^x}} \right)^x},\,x > 0y(x)=(xx)x,x>0, then d2xdy2+20{{{d^2}x} \over {d{y^2}}} + 20dy2d2x+20 at x = 1 is equal to ____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution