If R is the radius of the earth and the acceleration due to gravity on the surface of earth is g=π² ~m / s², then the length of the second's pendulum at a height h=2 R from the surface of earth will be,:

Gravitation: JEE Main 2024 Physics question

JEE Main 2024 · 1 Feb, Morning shift · Q7169

JEE Main 20241 Feb, Morning shiftPhysicsHardGravitation159× since 2002

\mathrm{R}

is the radius of the earth and the acceleration due to gravity on the surface of earth is

g=\pi^2 \mathrm{~m} / \mathrm{s}^2

, then the length of the second's pendulum at a height

\mathrm{h}=2 R

from the surface of earth will be, :

JEE Main 2024 · 1 Feb, Morning shift · Q7169

JEE Main 20241 Feb, Morning shiftPhysicsHardGravitation159× since 2002

\mathrm{R}

is the radius of the earth and the acceleration due to gravity on the surface of earth is

g=\pi^2 \mathrm{~m} / \mathrm{s}^2

, then the length of the second's pendulum at a height

\mathrm{h}=2 R

from the surface of earth will be, :