JEE Main 202429 Jan, Morning shiftMathematicsHardComplex Numbers and Quadratic Equations264× since 2002If z=12−2iz=\frac{1}{2}-2 iz=21−2i is such that ∣z+1∣=αz+β(1+i),i=−1|z+1|=\alpha z+\beta(1+i), i=\sqrt{-1}∣z+1∣=αz+β(1+i),i=−1 and α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R, then α+β\alpha+\betaα+β is equal toAOption A. 2BOption B. −-−4COption C. 3DOption D. −-−1CheckSkip · show solution
