JEE Main 2005Annual, Paper 1MathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002If xxx is so small that x3{x^3}x3 and higher powers of xxx may be neglected, then (1+x)32−(1+12x)3(1−x)12{{{{\left( {1 + x} \right)}^{{3 \over 2}}} - {{\left( {1 + {1 \over 2}x} \right)}^3}} \over {{{\left( {1 - x} \right)}^{{1 \over 2}}}}}(1−x)21(1+x)23−(1+21x)3 may be approximated asAOption A. 1−38x21 - {3 \over 8}{x^2}1−83x2BOption B. 3x+38x23x + {3 \over 8}{x^2}3x+83x2COption C. −38x2- {3 \over 8}{x^2}−83x2DOption D. x2−38x2{x \over 2} - {3 \over 8}{x^2}2x−83x2CheckSkip · show solution