JEE Main 20205 Sep, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002If α\alphaα is positive root of the equation, p(x) = x² - x - 2 = 0, then limx→α+1−cos(p(x))x+α−4\mathop {\lim }\limits_{x \to {\alpha ^ + }} {{\sqrt {1 - \cos \left( {p\left( x \right)} \right)} } \over {x + \alpha - 4}}x→α+limx+α−41−cos(p(x)) is equal to :AOption A. 12{1 \over \sqrt2}21BOption B. 12{1 \over 2}21COption C. 32{3 \over \sqrt2}23DOption D. 32{3 \over 2}23CheckSkip · show solution
