JEE Main 201910 Apr, Evening shiftMathematicsEasyIntegral Calculus369× since 2002If ∫x5e−x2dx=g(x)e−x2+c\int {{x^5}} {e^{ - {x^2}}}dx = g\left( x \right){e^{ - {x^2}}} + c∫x5e−x2dx=g(x)e−x2+c, where c is a constant of integration, then ggg(–1) is equal to :AOption A. 1BOption B. - 1COption C. −52- {5 \over 2}−25DOption D. −12- {1 \over 2}−21CheckSkip · show solution
