JEE Main 201911 Jan, Evening shiftMathematicsEasyIntegral Calculus369× since 2002If ∫x+12x−1 dx\int {{{x + 1} \over {\sqrt {2x - 1} }}} \,dx∫2x−1x+1dx = f(x) 2x−1\sqrt {2x - 1}2x−1 + C, where C is a constant of integration, then f(x) is equal to :AOption A. 23{2 \over 3}32 (x −-− 4)BOption B. 13{1 \over 3}31 (x + 4)COption C. 13{1 \over 3}31 (x + 1)DOption D. 23{2 \over 3}32 (x + 2)CheckSkip · show solution
