JEE Main 20179 Apr, Morning shiftMathematicsMediumIntegral Calculus369× since 2002If ∫12dx(x2−2x+4)32=kk+5,\int\limits_1^2 {{{dx} \over {{{\left( {{x^2} - 2x + 4} \right)}^{{3 \over 2}}}}}} = {k \over {k + 5}},1∫2(x2−2x+4)23dx=k+5k, then k is equal to :AOption A. 1BOption B. 2COption C. 3DOption D. 4CheckSkip · show solution