JEE Main 202628 Jan, Morning shiftMathematicsEasyIntegral Calculus369× since 2002If ∫(1−5cos2xsin5xcos2x)dx=f(x)+C\int\left(\frac{1-5\cos^2x}{\sin^5x\cos^2x}\right)dx=f(x)+C∫(sin5xcos2x1−5cos2x)dx=f(x)+C, where C is the constant of integration, then f(π6)−f(π4)f\left(\frac\pi6\right)-f\left(\frac\pi4\right)f(6π)−f(4π) is equal toAOption A. 13(26+3)\frac{1}{\sqrt3}(26+\sqrt3)31(26+3)BOption B. 43(8−6)\frac{4}{\sqrt3}(8-\sqrt6)34(8−6)COption C. 13(26−3)\frac{1}{\sqrt3}(26-\sqrt3)31(26−3)DOption D. 23(4+6)\frac{2}{\sqrt3}(4+\sqrt6)32(4+6)CheckSkip · show solution