JEE Main 20208 Jan, Morning shiftMathematicsMediumIntegral Calculus369× since 2002If ∫cosxdxsin3x(1+sin6x)2/3=f(x)(1+sin6x)1/λ+c\int {{{\cos xdx} \over {{{\sin }^3}x{{\left( {1 + {{\sin }^6}x} \right)}^{2/3}}}}} = f\left( x \right){\left( {1 + {{\sin }^6}x} \right)^{1/\lambda }} + c∫sin3x(1+sin6x)2/3cosxdx=f(x)(1+sin6x)1/λ+c where c is a constant of integration, then λf(π3)\lambda f\left( {{\pi \over 3}} \right)λf(3π) is equal toAOption A. 98{9 \over 8}89BOption B. 2COption C. -2DOption D. −98-{9 \over 8}−89CheckSkip · show solution