If ∫ (cos θ)/(5 + 7 sin θ - 2 cos ²θ) dθ = A log e | B(θ) | + C, where C is a constant of integration, then (B(θ))/A can be:

(C) (5(2 sin θ + 1))/(sin θ + 3)

(A) (2 sin θ + 1)/(5(sin θ + 3))

(B) (2 sin θ + 1)/(sin θ + 3)

(D) (5(sin θ + 3))/(2 sin θ + 1)

Integral Calculus: JEE Main 2020 Mathematics question

JEE Main 2020 · 5 Sep, Evening shift · Q4022

JEE Main 20205 Sep, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

\int {{{\cos \theta } \over {5 + 7\sin \theta - 2{{\cos }^2}\theta }}} d\theta

= A

{\log _e}\left| {B\left( \theta \right)} \right| + C

, where C is a constant of integration, then

{{{B\left( \theta \right)} \over A}}

can be :

JEE Main 2020 · 5 Sep, Evening shift · Q4022

JEE Main 20205 Sep, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

\int {{{\cos \theta } \over {5 + 7\sin \theta - 2{{\cos }^2}\theta }}} d\theta

= A

{\log _e}\left| {B\left( \theta \right)} \right| + C

, where C is a constant of integration, then

{{{B\left( \theta \right)} \over A}}

can be :