JEE Main 201815 Apr, Evening shiftMathematicsMediumIntegral Calculus369× since 2002If ∫2x+57−6x−x2 dx=A7−6x−x2+Bsin−1(x+34)+C\int {{{2x + 5} \over {\sqrt {7 - 6x - {x^2}} }}} \,\,dx = A\sqrt {7 - 6x - {x^2}} + B{\sin ^{ - 1}}\left( {{{x + 3} \over 4}} \right) + C∫7−6x−x22x+5dx=A7−6x−x2+Bsin−1(4x+3)+C (where C is a constant of integration), then the ordered pair (A, B) is equal to :AOption A. (2, 1)BOption B. (−-− 2, −-−1)COption C. (−-− 2, 1)DOption D. (2, −-−1)CheckSkip · show solution
