JEE Main 202127 Jul, Evening shiftMathematicsMediumIntegral Calculus369× since 2002If ∫0π(sin3x)e−sin2xdx=α−βe∫01tetdt\int_0^\pi {({{\sin }^3}x){e^{ - {{\sin }^2}x}}dx = \alpha - {\beta \over e}\int_0^1 {\sqrt t {e^t}dt} }∫0π(sin3x)e−sin2xdx=α−eβ∫01tetdt, then α\alphaα + β\betaβ is equal to ____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
