JEE Main 20206 Sep, Morning shiftMathematicsHardIntegral Calculus369× since 2002If I₁ = ∫01(1−x50)100dx\int\limits_0^1 {{{\left( {1 - {x^{50}}} \right)}^{100}}} dx0∫1(1−x50)100dx and I₂ = ∫01(1−x50)101dx\int\limits_0^1 {{{\left( {1 - {x^{50}}} \right)}^{101}}} dx0∫1(1−x50)101dx such that I₂ = α\alphaαI₁ then α\alphaα equals to :AOption A. 50515050{{5051} \over {5050}}50505051BOption B. 50505051{{5050} \over {5051}}50515050COption C. 50505049{{5050} \over {5049}}50495050DOption D. 50495050{{5049} \over {5050}}50505049CheckSkip · show solution
