JEE Main 20238 Apr, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If for z=α+iβ,∣z+2∣=z+4(1+i)z=\alpha+i \beta,|z+2|=z+4(1+i)z=α+iβ,∣z+2∣=z+4(1+i), then α+β\alpha+\betaα+β and αβ\alpha \betaαβ are the roots of the equation :AOption A. x2+2x−3=0x^{2}+2 x-3=0x2+2x−3=0BOption B. x2+3x−4=0x^{2}+3 x-4=0x2+3x−4=0COption C. x2+x−12=0x^{2}+x-12=0x2+x−12=0DOption D. x2+7x+12=0x^{2}+7 x+12=0x2+7x+12=0CheckSkip · show solution
