If for a positive integer n, the quadratic equation x(x + 1) + (x + 1)(x + 2) +.... + (x + n - 1)(x + n) = 10n has two consecutive integral solutions, then n is equal to:

Complex Numbers and Quadratic Equations: JEE Main 2017 Mathematics question

JEE Main 2017 · Session, Shift 1 · Q5125

JEE Main 2017Session, Shift 1MathematicsMediumComplex Numbers and Quadratic Equations264× since 2002

If for a positive integer n, the quadratic equation

x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right)

+ .... + \left( {x + \overline {n - 1} } \right)\left( {x + n} \right)

= 10n

has two consecutive integral solutions, then n is equal to :

JEE Main 2017 · Session, Shift 1 · Q5125

JEE Main 2017Session, Shift 1MathematicsMediumComplex Numbers and Quadratic Equations264× since 2002

If for a positive integer n, the quadratic equation

x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right)

+ .... + \left( {x + \overline {n - 1} } \right)\left( {x + n} \right)

= 10n

has two consecutive integral solutions, then n is equal to :