JEE Main 202324 Jan, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002If f(x)=x3−x2f′(1)+xf′′(2)−f′′′(3),x∈Rf(x) = {x^3} - {x^2}f'(1) + xf''(2) - f'''(3),x \in \mathbb{R}f(x)=x3−x2f′(1)+xf′′(2)−f′′′(3),x∈R, thenAOption A. 2f(0)−f(1)+f(3)=f(2)2f(0) - f(1) + f(3) = f(2)2f(0)−f(1)+f(3)=f(2)BOption B. f(1)+f(2)+f(3)=f(0)f(1) + f(2) + f(3) = f(0)f(1)+f(2)+f(3)=f(0)COption C. f(3)−f(2)=f(1)f(3) - f(2) = f(1)f(3)−f(2)=f(1)DOption D. 3f(1)+f(2)=f(3)3f(1) + f(2) = f(3)3f(1)+f(2)=f(3)CheckSkip · show solution
