JEE Main 20198 Apr, Morning shiftMathematicsEasySets, Relations and Functions168× since 2002If f(x)=loge(1−x1+x)f(x) = {\log _e}\left( {{{1 - x} \over {1 + x}}} \right)f(x)=loge(1+x1−x), ∣x∣<1\left| x \right| < 1∣x∣<1 then f(2x1+x2)f\left( {{{2x} \over {1 + {x^2}}}} \right)f(1+x22x) is equal toAOption A. 2f(x²)BOption B. 2f(x)COption C. (f(x))²DOption D. -2f(x)CheckSkip · show solution