JEE Main 202125 Jul, Evening shiftMathematicsMediumIntegral Calculus369× since 2002If f(x)={∫0x(5+∣1−t∣)dt,x>25x+1,x≤2f(x) = \left\{ {\matrix{ {\int\limits_0^x {\left( {5 + \left| {1 - t} \right|} \right)dt,} } & {x > 2} \cr {5x + 1,} & {x \le 2} \cr } } \right.f(x)=⎩⎨⎧0∫x(5+∣1−t∣)dt,5x+1,x>2x≤2, thenAOption A. f(x) is not continuous at x = 2BOption B. f(x) is everywhere differentiableCOption C. f(x) is continuous but not differentiable at x = 2DOption D. f(x) is not differentiable at x = 1CheckSkip · show solution
