If f((x - 4)/(x + 2)) = 2x + 1, (x R - 1, - 2), then ∫ f (x)dx is equal to: (where C is a constant of integration)

(B) - 12 log e | 1 - x | - 3x + C

(A) 12 log e | 1 - x | + 3x + C

(C) 12 log e | 1 - x | - 3x + C

(D) - 12 log e | 1 - x | + 3x + C

Integral Calculus: JEE Main 2018 Mathematics question

JEE Main 2018 · 15 Apr, Morning shift · Q4046

JEE Main 201815 Apr, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

f\left( {{{x - 4} \over {x + 2}}} \right) = 2x + 1,

\in

-

{1,

-

2}), then

\int f \left( x \right)dx

is equal to : (where C is a constant of integration)

JEE Main 2018 · 15 Apr, Morning shift · Q4046

JEE Main 201815 Apr, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

f\left( {{{x - 4} \over {x + 2}}} \right) = 2x + 1,

\in

-

{1,

-

2}), then

\int f \left( x \right)dx

is equal to : (where C is a constant of integration)