JEE Main 202229 Jul, Morning shiftMathematicsMediumIntegral Calculus369× since 2002If f(α)=∫1αlog10t1+tdt,α>0f(\alpha)=\int\limits_{1}^{\alpha} \frac{\log _{10} \mathrm{t}}{1+\mathrm{t}} \mathrm{dt}, \alpha>0f(α)=1∫α1+tlog10tdt,α>0, then f(e3)+f(e−3)f\left(\mathrm{e}^{3}\right)+f\left(\mathrm{e}^{-3}\right)f(e3)+f(e−3) is equal to :AOption A. 9BOption B. 92\frac{9}{2}29COption C. 9loge(10)\frac{9}{\log _{e}(10)}loge(10)9DOption D. 92loge(10)\frac{9}{2 \log _{e}(10)}2loge(10)9CheckSkip · show solution