If e₁ and e₂ are the eccentricities of the ellipse, (x²)/18 + (y²)/4 = 1 and the hyperbola, (x²)/9 - (y²)/4 = 1 respectively and (e₁, e₂) is a point on the ellipse, 15x² + 3y² = k, then k is equal to:

Coordinate Geometry: JEE Main 2020 Mathematics question

JEE Main 2020 · 9 Jan, Morning shift · Q3968

JEE Main 20209 Jan, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002

If e₁ and e₂ are the eccentricities of the ellipse,

{{{x^2}} \over {18}} + {{{y^2}} \over 4} = 1

and the hyperbola,

{{{x^2}} \over 9} - {{{y^2}} \over 4} = 1

respectively and (e₁, e₂) is a point on the ellipse, 15x² + 3y² = k, then k is equal to :

JEE Main 2020 · 9 Jan, Morning shift · Q3968

JEE Main 20209 Jan, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002

If e₁ and e₂ are the eccentricities of the ellipse,

{{{x^2}} \over {18}} + {{{y^2}} \over 4} = 1

and the hyperbola,

{{{x^2}} \over 9} - {{{y^2}} \over 4} = 1

respectively and (e₁, e₂) is a point on the ellipse, 15x² + 3y² = k, then k is equal to :