If dy/dx + 2y tan x = sin x, 0 < x < (π)/2 and y((π)/3) = 0, then the maximum value of y(x) is:

Differential Equations: JEE Main 2022 Mathematics question

JEE Main 2022 · 26 Jul, Morning shift · Q3547

JEE Main 202226 Jul, Morning shiftMathematicsMediumDifferential Equations163× since 2002

{{dy} \over {dx}} + 2y\tan x = \sin x,\,0 < x < {\pi \over 2}

and

y\left( {{\pi \over 3}} \right) = 0

, then the maximum value of

y(x)

is :

JEE Main 2022 · 26 Jul, Morning shift · Q3547

JEE Main 202226 Jul, Morning shiftMathematicsMediumDifferential Equations163× since 2002

{{dy} \over {dx}} + 2y\tan x = \sin x,\,0 < x < {\pi \over 2}

and

y\left( {{\pi \over 3}} \right) = 0

, then the maximum value of

y(x)

is :