JEE Main 202227 Jun, Morning shiftMathematicsMediumDifferential Equations163× since 2002If dydx+2x−y(2y−1)2x−1=0{{dy} \over {dx}} + {{{2^{x - y}}({2^y} - 1)} \over {{2^x} - 1}} = 0dxdy+2x−12x−y(2y−1)=0, x, y > 0, y(1) = 1, then y(2) is equal to :AOption A. 2+log232 + {\log _2}32+log23BOption B. 2+log322 + {\log _3}22+log32COption C. 2−log322 - {\log _3}22−log32DOption D. 2−log232 - {\log _2}32−log23CheckSkip · show solution
