JEE Main 2007Annual, Paper 1MathematicsEasyMatrices and Determinants245× since 2002If D=∣11111+x1111+y∣D = \left| {\matrix{ 1 & 1 & 1 \cr 1 & {1 + x} & 1 \cr 1 & 1 & {1 + y} \cr } } \right|D=11111+x1111+y for x≠0,y≠0,x \ne 0,y \ne 0,x=0,y=0, then DDD is :AOption A. divisible by xxx but not yyyBOption B. divisible by yyy but not xxxCOption C. divisible by neither xxx nor yyyDOption D. divisible by both xxx and yyyCheckSkip · show solution
