JEE Main 2018Session, Shift 1MathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If α,β∈C\alpha ,\beta \in Cα,β∈C are the distinct roots of the equation x² - x + 1 = 0, then α101+β107{\alpha ^{101}} + {\beta ^{107}}α101+β107 is equal to :AOption A. 2BOption B. -1COption C. 0DOption D. 1CheckSkip · show solution