JEE Main 20264 Apr, Evening shiftMathematicsEasyIntegral Calculus369× since 2002If α=1\alpha=1α=1 and β=1+i2\beta=1+i\sqrt2β=1+i2, where i=−1i=\sqrt{-1}i=−1 are two roots of the equation x3+ax2+bx+c=0x^3+ax^2+bx+c=0x3+ax2+bx+c=0, a,b,c∈Ra,b,c\in\mathbb{R}a,b,c∈R, then ∫−11(x3+ax2+bx+c)dx\int_{-1}^{1}\left(x^3+ax^2+bx+c\right)dx∫−11(x3+ax2+bx+c)dx is equal to:AOption A. −2-2−2BOption B. −4-4−4COption C. −8-8−8DOption D. −10-10−10CheckSkip · show solution
