JEE Main 202120 Jul, Morning shiftPhysicsHardKinematics177× since 2002If A→\overrightarrow AA and B→\overrightarrow BB are two vectors satisfying the relation A→\overrightarrow AA . B→\overrightarrow BB = ∣A→×B→∣\left| {\overrightarrow A \times \overrightarrow B } \right|A×B. Then the value of ∣A→−B→∣\left| {\overrightarrow A - \overrightarrow B } \right|A−B will be :AOption A. A2+B2+2AB\sqrt {{A^2} + {B^2} + \sqrt 2 AB}A2+B2+2ABBOption B. A2+B2\sqrt {{A^2} + {B^2}}A2+B2COption C. A2+B2−2AB\sqrt {{A^2} + {B^2} - \sqrt 2 AB}A2+B2−2ABDOption D. A2+B2+2AB\sqrt {{A^2} + {B^2} + 2AB}A2+B2+2ABCheckSkip · show solution
