If a>0 and discriminant of a x² + 2bx + c is -ve, then | a b ax + b b c bx + c ax + b bx + c 0 | is equal to

(B) (ac - b²)(a x² + 2bx + c)

Matrices and Determinants: JEE Main 2002 Mathematics question

JEE Main 2002 · Annual, Paper 1 · Q4433

JEE Main 2002Annual, Paper 1MathematicsMediumMatrices and Determinants245× since 2002

a>0

and discriminant of

\,a{x^2} + 2bx + c

-ve

, then

\left| {\matrix{ a & b & {ax + b} \cr b & c & {bx + c} \cr {ax + b} & {bx + c} & 0 \cr } } \right|

is equal to

JEE Main 2002 · Annual, Paper 1 · Q4433

JEE Main 2002Annual, Paper 1MathematicsMediumMatrices and Determinants245× since 2002

a>0

and discriminant of

\,a{x^2} + 2bx + c

-ve

, then

\left| {\matrix{ a & b & {ax + b} \cr b & c & {bx + c} \cr {ax + b} & {bx + c} & 0 \cr } } \right|

is equal to