JEE Main 20198 Apr, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If α\alphaα and β\betaβ be the roots of the equation x² – 2x + 2 = 0, then the least value of n for which (αβ)n=1{\left( {{\alpha \over \beta }} \right)^n} = 1(βα)n=1 is :AOption A. 2BOption B. 5COption C. 4DOption D. 3CheckSkip · show solution