If θ ₁ and θ ₂ be respectively the smallest and the largest values of θ in (0, 2 π) - π which satisfy the equation, 2cot² θ - 5/(sin θ) + 4 = 0, then ∫ θ ₁ ^(θ ₂) cos ²3θ dθ is equal to:

Integral Calculus: JEE Main 2020 Mathematics question

JEE Main 2020 · 7 Jan, Evening shift · Q3389

JEE Main 20207 Jan, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

\theta

₁ and

\theta

₂ be respectively the smallest and the largest values of

\theta

in (0, 2

\pi

) - {

\pi

} which satisfy the equation, 2cot²

\theta

{5 \over {\sin \theta }}

+ 4 = 0, then

\int\limits_{{\theta _1}}^{{\theta _2}} {{{\cos }^2}3\theta d\theta }

is equal to :

JEE Main 2020 Integral Calculus Question with Solution (7 Jan Evening shift, Q3389) | JEE Arc