JEE Main 201912 Apr, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002If α\alphaα and β\betaβ are the roots of the equation 375x² – 25x – 2 = 0, then limn→∞∑r=1nαr+limn→∞∑r=1nβr\mathop {\lim }\limits_{n \to \infty } \sum\limits_{r = 1}^n {{\alpha ^r}} + \mathop {\lim }\limits_{n \to \infty } \sum\limits_{r = 1}^n {{\beta ^r}}n→∞limr=1∑nαr+n→∞limr=1∑nβr is equal to :AOption A. 7116{7 \over {116}}1167BOption B. 29348{{29} \over {348}}34829COption C. 112{1 \over {12}}121DOption D. 21346{{21} \over {346}}34621CheckSkip · show solution
