JEE Main 202120 Jul, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If α\alphaα and β\betaβ are the distinct roots of the equation x2+(3)1/4x+31/2=0{x^2} + {(3)^{1/4}}x + {3^{1/2}} = 0x2+(3)1/4x+31/2=0, then the value of α96(α12−1)+β96(β12−1){\alpha ^{96}}({\alpha ^{12}} - 1) + {\beta ^{96}}({\beta ^{12}} - 1)α96(α12−1)+β96(β12−1) is equal to :AOption A. 56 ×\times× 3²⁵BOption B. 56 ×\times× 3²⁴COption C. 52 ×\times× 3²⁴DOption D. 28 ×\times× 3²⁵CheckSkip · show solution
