JEE Main 202628 Jan, Morning shiftMathematicsEasySets, Relations and Functions168× since 2002If g(x)=3x2+2x−3g(x)=3x^2+2x-3g(x)=3x2+2x−3, f(0)=−3f(0)=-3f(0)=−3 and 4g(f(x))=3x2−32x+724g(f(x))=3x^2-32x+724g(f(x))=3x2−32x+72, then f(g(2))f(g(2))f(g(2)) is equal to:AOption A. 72\frac{7}{2}27BOption B. −256-\frac{25}{6}−625COption C. 256\frac{25}{6}625DOption D. −72-\frac{7}{2}−27CheckSkip · show solution
